Un triángulo heptagonal es un triángulo escaleno obtuso cuyos vértices coinciden con el primer, segundo y cuarto vértices de un heptágono regular (desde un vértice inicial arbitrario). Por lo tanto, sus tres lados coinciden con un lado y con las diagonales adyacentes más cortas y más largas de un heptágono regular. Todos los triángulos heptagonales son similares (tienen la misma forma), por lo que se conocen colectivamente como el triángulo heptagonal. Sus ángulos miden π / 7 , 2 π / 7 , {\displaystyle \pi /7,2\pi /7,} y 4 π / 7 , {\displaystyle 4\pi /7,} y es el único triángulo con ángulos en las relaciones 1: 2: 4. El triángulo heptagonal tiene varias propiedades notables.

Puntos clave

El centro de nueve puntos del triángulo heptagonal es también su primer punto de Brocard.[1]: Propos. 12 

El segundo punto de Brocard se encuentra en el círculo de nueve puntos.[2]: p. 19 

El circuncentro y los puntos de Fermat de un triángulo heptagonal forman un triángulo equilátero.[1]: Thm. 22 

La distancia entre el circuncentro O y el ortocentro H viene dada por[2]: p. 19 

O H = R 2 , {\displaystyle OH=R{\sqrt {2}},}

donde R es el circunradio. La distancia al cuadrado desde el incentro I al ortocentro es[2]: p. 19 

I H 2 = R 2 4 r 2 2 , {\displaystyle IH^{2}={\frac {R^{2} 4r^{2}}{2}},}

donde r es el inradio.

Las dos tangentes desde el ortocentro hasta el circuncírculo son mutuamente perpendiculares.[2]: p. 19 

Relaciones de distancias

Lados

Los lados del triángulo heptagonal a < b < c coinciden respectivamente con el lado del heptágono regular, diagonal más corta y diagonal más larga. Satisfacen que[3]: Lemma 1 

a 2 = c ( c b ) , b 2 = a ( c a ) , c 2 = b ( a b ) , 1 a = 1 b 1 c {\displaystyle {\begin{aligned}a^{2}&=c(c-b),\\[5pt]b^{2}&=a(c a),\\[5pt]c^{2}&=b(a b),\\[5pt]{\frac {1}{a}}&={\frac {1}{b}} {\frac {1}{c}}\end{aligned}}}

(la última[2]: p. 13  es la ecuación óptica) y por lo tanto

a b a c = b c , {\displaystyle ab ac=bc,}

y[3]: Coro. 2 

b 3 2 b 2 c b c 2 c 3 = 0 , {\displaystyle b^{3} 2b^{2}c-bc^{2}-c^{3}=0,}
c 3 2 c 2 a c a 2 a 3 = 0 , {\displaystyle c^{3}-2c^{2}a-ca^{2} a^{3}=0,}
a 3 2 a 2 b a b 2 b 3 = 0. {\displaystyle a^{3}-2a^{2}b-ab^{2} b^{3}=0.}

Por lo tanto, -b/c, c/a y a/b satisfacen la ecuación cúbica

t 3 2 t 2 t 1 = 0. {\displaystyle t^{3}-2t^{2}-t 1=0.}

La relación entre los lados es

b = 2 cos ( π 7 ) a , c = ( 1 2 cos ( 2 π 7 ) ) a . {\displaystyle b=2\cos \left({\frac {\pi }{7}}\right)\cdot a,\qquad c=\left(1 2\cos \left({\frac {2\pi }{7}}\right)\right)\cdot a.}

y las raíces de esta ecuación son:

{ t 1 = 1 2 cos ( π 7 ) t 2 = 1 2 cos ( 2 π 7 ) t 3 = 4 cos ( 2 π 7 ) cos ( 3 π 7 ) {\displaystyle {\begin{cases}t_{1}=1-2\cos \left({\frac {\pi }{7}}\right)\\t_{2}=1 2\cos \left({\frac {2\pi }{7}}\right)\\t_{3}=4\cos \left({\frac {2\pi }{7}}\right)\cos \left({\frac {3\pi }{7}}\right)\end{cases}}}


También se tiene que[4]

a 2 b c , b 2 c a , c 2 a b {\displaystyle {\frac {a^{2}}{bc}},\quad -{\frac {b^{2}}{ca}},\quad -{\frac {c^{2}}{ab}}}

satisface la ecuación cúbica

t 3 4 t 2 3 t 1 = 0 {\displaystyle t^{3} 4t^{2} 3t-1=0}

y las raíces de esta ecuación son:

{ t 1 = 1 2 cos ( π 7 ) t 2 = 1 2 cos ( 2 π 7 ) t 3 = 4 cos ( 2 π 7 ) cos ( 3 π 7 ) 2 {\displaystyle {\begin{cases}t_{1}=-1-2\cos \left({\frac {\pi }{7}}\right)\\t_{2}=-1 2\cos \left({\frac {2\pi }{7}}\right)\\t_{3}=4\cos \left({\frac {2\pi }{7}}\right)\cos \left({\frac {3\pi }{7}}\right)-2\end{cases}}}

También se tiene que[4]

a 3 b c 2 , b 3 c a 2 , c 3 a b 2 {\displaystyle {\frac {a^{3}}{bc^{2}}},\quad -{\frac {b^{3}}{ca^{2}}},\quad {\frac {c^{3}}{ab^{2}}}}

satisface la ecuación cúbica

t 3 t 2 9 t 1 = 0 {\displaystyle t^{3}-t^{2}-9t 1=0}

y las raíces de esta ecuación son:

{ t 1 = 1 4 cos ( π 7 ) t 2 = 1 4 cos ( 2 π 7 ) t 3 = 8 cos ( 2 π 7 ) cos ( 3 π 7 ) 1 {\displaystyle {\begin{cases}t_{1}=1-4\cos \left({\frac {\pi }{7}}\right)\\t_{2}=1 4\cos \left({\frac {2\pi }{7}}\right)\\t_{3}=8\cos \left({\frac {2\pi }{7}}\right)\cos \left({\frac {3\pi }{7}}\right)-1\end{cases}}}

Así mismo, los valores[4]

a 3 b 2 c , b 3 c 2 a , c 3 a 2 b {\displaystyle {\frac {a^{3}}{b^{2}c}},\quad {\frac {b^{3}}{c^{2}a}},\quad -{\frac {c^{3}}{a^{2}b}}}

satisfacen la ecuación cúbica

t 3 5 t 2 8 t 1 = 0 {\displaystyle t^{3} 5t^{2}-8t 1=0}

y las raíces de esta ecuación son:

{ t 1 = 2 [ cos ( π 7 ) 2 cos ( 2 π 7 ) 1 ] t 2 = 6 cos ( π 7 ) 2 cos ( 2 π 7 ) 3 t 3 = 2 [ 3 cos ( 2 π 7 ) 2 cos ( π 7 ) ] {\displaystyle {\begin{cases}t_{1}=-2\left[\cos \left({\frac {\pi }{7}}\right) 2\cos \left({\frac {2\pi }{7}}\right) 1\right]\\t_{2}=6\cos \left({\frac {\pi }{7}}\right)-2\cos \left({\frac {2\pi }{7}}\right)-3\\t_{3}=2\left[3\cos \left({\frac {2\pi }{7}}\right)-2\cos \left({\frac {\pi }{7}}\right)\right]\end{cases}}}

También se tiene que[2]: p. 14 

b 2 a 2 = a c , {\displaystyle b^{2}-a^{2}=ac,}
c 2 b 2 = a b , {\displaystyle c^{2}-b^{2}=ab,}
a 2 c 2 = b c , {\displaystyle a^{2}-c^{2}=-bc,}

y[2]: p. 15 

b 2 a 2 c 2 b 2 a 2 c 2 = 5. {\displaystyle {\frac {b^{2}}{a^{2}}} {\frac {c^{2}}{b^{2}}} {\frac {a^{2}}{c^{2}}}=5.}

Por otro lado[4]

a b b c c a = 0 , {\displaystyle ab-bc ca=0,}
a 3 b b 3 c c 3 a = 0 , {\displaystyle a^{3}b-b^{3}c c^{3}a=0,}
a 4 b b 4 c c 4 a = 0 , {\displaystyle a^{4}b b^{4}c-c^{4}a=0,}
a 11 b 3 b 11 c 3 c 11 a 3 = 0. {\displaystyle a^{11}b^{3}-b^{11}c^{3} c^{11}a^{3}=0.}

No hay otro par de números (m, n), tales que m, n > 0 y que m, n <2000, que cumplan [cita requerida]

a m b n ± b m c n ± c m a n = 0. {\displaystyle a^{m}b^{n}\pm b^{m}c^{n}\pm c^{m}a^{n}=0.}

Alturas

Las alturas ha, hb y hc satisfacen

h a = h b h c {\displaystyle h_{a}=h_{b} h_{c}} [2]: p. 13 

y

h a 2 h b 2 h c 2 = a 2 b 2 c 2 2 . {\displaystyle h_{a}^{2} h_{b}^{2} h_{c}^{2}={\frac {a^{2} b^{2} c^{2}}{2}}.} [2]: p. 14 

La altura desde el lado b (ángulo opuesto B) es la mitad de la bisectriz del ángulo interno w A {\displaystyle w_{A}} de A:[2]: p. 19 

2 h b = w A . {\displaystyle 2h_{b}=w_{A}.}

Aquí el ángulo A es el ángulo más pequeño y B es el segundo ángulo más pequeño.

Bisectrices

Se tienen las siguientes propiedades de las bisectrices w A , w B , {\displaystyle w_{A},w_{B},} y w C {\displaystyle w_{C}} de los ángulos A, B y C respectivamente:[2]: p. 16 

w A = b c , {\displaystyle w_{A}=b c,}
w B = c a , {\displaystyle w_{B}=c-a,}
w C = b a . {\displaystyle w_{C}=b-a.}

Circunradio, inradio y exinradios

El área del triángulo es[5]

A = 7 4 R 2 , {\displaystyle A={\frac {\sqrt {7}}{4}}R^{2},}

donde R es el circunradio del triángulo.

Se tiene que[2]: p. 12 

a 2 b 2 c 2 = 7 R 2 . {\displaystyle a^{2} b^{2} c^{2}=7R^{2}.}

También se tiene que[6]

a 4 b 4 c 4 = 21 R 4 . {\displaystyle a^{4} b^{4} c^{4}=21R^{4}.}
a 6 b 6 c 6 = 70 R 6 . {\displaystyle a^{6} b^{6} c^{6}=70R^{6}.}

La relación r R = 2 cos ( π 7 ) 3 2 {\displaystyle {\frac {r}{R}}=2\cos \left({\frac {\pi }{7}}\right)-{\frac {3}{2}}} del inradio respecto al circunradio es la solución positiva de la ecuación cúbica[5]

8 x 3 28 x 2 14 x 7 = 0 {\displaystyle 8x^{3} 28x^{2} 14x-7=0}

siendo las otras dos raíces de esta ecuación 2 cos ( 3 π 7 ) 3 2 {\displaystyle 2\cos \left({\frac {3\pi }{7}}\right)-{\frac {3}{2}}} y 2 cos ( 5 π 7 ) 3 2 {\displaystyle 2\cos \left({\frac {5\pi }{7}}\right)-{\frac {3}{2}}} .

La relación r a r b r c R = 2 cos ( π 7 ) 5 2 {\displaystyle {\frac {r_{a} r_{b} r_{c}}{R}}=2\cos \left({\frac {\pi }{7}}\right) {\frac {5}{2}}} de la suma de los exinradios respecto al circunradio es la mayor de las raíces de la ecuación cúbica:

8 x 3 68 x 2 174 x 127 = 0 {\displaystyle 8x^{3}-68x^{2} 174x-127=0}

siendo las otras dos raíces de esta ecuación 2 cos ( 3 π 7 ) 5 2 {\displaystyle 2\cos \left({\frac {3\pi }{7}}\right) {\frac {5}{2}}} y 2 cos ( 5 π 7 ) 5 2 {\displaystyle 2\cos \left({\frac {5\pi }{7}}\right) {\frac {5}{2}}} .

La relación 1 r a 1 r b 1 r c R = 4 cos ( 2 π 7 ) {\displaystyle {\frac {{\frac {1}{r_{a}}} {\frac {1}{r_{b}}} {\frac {1}{r_{c}}}}{R}}=4\cos \left({\frac {2\pi }{7}}\right)} de la suma de los inversos de los exinradios respecto al circunradio es la única raíz positiva de la ecuación cúbica:

x 3 2 x 2 8 x 8 = 0 {\displaystyle x^{3} 2x^{2}-8x-8=0}

siendo las otras dos raíces de esta ecuación 4 cos ( 4 π 7 ) {\displaystyle 4\cos \left({\frac {4\pi }{7}}\right)} y 4 cos ( 6 π 7 ) {\displaystyle 4\cos \left({\frac {6\pi }{7}}\right)} .

Además,[2]: p. 15 

1 a 2 1 b 2 1 c 2 = 2 R 2 . {\displaystyle {\frac {1}{a^{2}}} {\frac {1}{b^{2}}} {\frac {1}{c^{2}}}={\frac {2}{R^{2}}}.}

También se tiene que[6]

1 a 4 1 b 4 1 c 4 = 2 R 4 . {\displaystyle {\frac {1}{a^{4}}} {\frac {1}{b^{4}}} {\frac {1}{c^{4}}}={\frac {2}{R^{4}}}.}
1 a 6 1 b 6 1 c 6 = 17 7 R 6 . {\displaystyle {\frac {1}{a^{6}}} {\frac {1}{b^{6}}} {\frac {1}{c^{6}}}={\frac {17}{7R^{6}}}.}

En general para todos los enteros n,

a 2 n b 2 n c 2 n = g ( n ) ( 2 R ) 2 n {\displaystyle a^{2n} b^{2n} c^{2n}=g(n)(2R)^{2n}}

donde

g ( 1 ) = 8 , g ( 0 ) = 3 , g ( 1 ) = 7 {\displaystyle g(-1)=8,\quad g(0)=3,\quad g(1)=7}

y

g ( n ) = 7 g ( n 1 ) 14 g ( n 2 ) 7 g ( n 3 ) . {\displaystyle g(n)=7g(n-1)-14g(n-2) 7g(n-3).}

Así mismo[6]

2 b 2 a 2 = 7 b R , 2 c 2 b 2 = 7 c R , 2 a 2 c 2 = 7 a R . {\displaystyle 2b^{2}-a^{2}={\sqrt {7}}bR,\quad 2c^{2}-b^{2}={\sqrt {7}}cR,\quad 2a^{2}-c^{2}=-{\sqrt {7}}aR.}

También se tiene que[4]

a 3 c b 3 a c 3 b = 7 R 4 , {\displaystyle a^{3}c b^{3}a-c^{3}b=-7R^{4},}
a 4 c b 4 a c 4 b = 7 7 R 5 , {\displaystyle a^{4}c-b^{4}a c^{4}b=7{\sqrt {7}}R^{5},}
a 11 c 3 b 11 a 3 c 11 b 3 = 7 3 17 R 14 . {\displaystyle a^{11}c^{3} b^{11}a^{3}-c^{11}b^{3}=-7^{3}17R^{14}.}

El exradio ra correspondiente al lado a es igual al radio de la circunferencia de los nueve puntos del triángulo heptagonal.[2]: p. 15 

Triángulo órtico

El triángulo órtico del triángulo heptagonal, con vértices en los pies de las alturas, es similar al triángulo heptagonal, con una relación de similitud de 1: 2. El triángulo heptagonal es el único triángulo obtuso que es similar a su triángulo órtico (el triángulo equilátero es el único agudo con esta propiedad).[2]: pp. 12–13 

Propiedades trigonométricas

Las diversas identidades trigonométricas asociadas con el triángulo heptagonal incluyen:[2]: pp. 13–14 [5]

A = π 7 , B = 2 π 7 , C = 4 π 7 . {\displaystyle A={\frac {\pi }{7}},\quad B={\frac {2\pi }{7}},\quad C={\frac {4\pi }{7}}.}
cos A = b / 2 a , cos B = c / 2 b , cos C = a / 2 c , {\displaystyle \cos A=b/2a,\quad \cos B=c/2b,\quad \cos C=-a/2c,} [4]: Proposition 10 
cos A cos B cos C = 1 8 , {\displaystyle \cos A\cos B\cos C=-{\frac {1}{8}},}
cos 2 A cos 2 B cos 2 C = 5 4 , {\displaystyle \cos ^{2}A \cos ^{2}B \cos ^{2}C={\frac {5}{4}},}
cos 4 A cos 4 B cos 4 C = 13 16 , {\displaystyle \cos ^{4}A \cos ^{4}B \cos ^{4}C={\frac {13}{16}},}
cot A cot B cot C = 7 , {\displaystyle \cot A \cot B \cot C={\sqrt {7}},}
cot 2 A cot 2 B cot 2 C = 5 , {\displaystyle \cot ^{2}A \cot ^{2}B \cot ^{2}C=5,}
csc 2 A csc 2 B csc 2 C = 8 , {\displaystyle \csc ^{2}A \csc ^{2}B \csc ^{2}C=8,}
csc 4 A csc 4 B csc 4 C = 32 , {\displaystyle \csc ^{4}A \csc ^{4}B \csc ^{4}C=32,}
sec 2 A sec 2 B sec 2 C = 24 , {\displaystyle \sec ^{2}A \sec ^{2}B \sec ^{2}C=24,}
sec 4 A sec 4 B sec 4 C = 416 , {\displaystyle \sec ^{4}A \sec ^{4}B \sec ^{4}C=416,}
sen A sen B sen C = 7 8 , {\displaystyle \operatorname {sen} A\operatorname {sen} B\operatorname {sen} C={\frac {\sqrt {7}}{8}},}
sen 2 A sen 2 B sen 2 C = 7 64 , {\displaystyle \operatorname {sen} ^{2}A\operatorname {sen} ^{2}B\operatorname {sen} ^{2}C={\frac {7}{64}},}
sen 2 A sen 2 B sen 2 C = 7 4 , {\displaystyle \operatorname {sen} ^{2}A \operatorname {sen} ^{2}B \operatorname {sen} ^{2}C={\frac {7}{4}},}
sen 4 A sen 4 B sen 4 C = 21 16 , {\displaystyle \operatorname {sen} ^{4}A \operatorname {sen} ^{4}B \operatorname {sen} ^{4}C={\frac {21}{16}},}
tan A tan B tan C = tan A tan B tan C = 7 , {\displaystyle \tan A\tan B\tan C=\tan A \tan B \tan C=-{\sqrt {7}},}
tan 2 A tan 2 B tan 2 C = 21. {\displaystyle \tan ^{2}A \tan ^{2}B \tan ^{2}C=21.}

La ecuación cúbica

64 y 3 112 y 2 56 y 7 = 0 {\displaystyle 64y^{3}-112y^{2} 56y-7=0}

tiene soluciones[2]: p. 14  sen 2 π 7 , sen 2 2 π 7 , {\displaystyle \operatorname {sen} ^{2}{\frac {\pi }{7}},\operatorname {sen} ^{2}{\frac {2\pi }{7}},} y sen 2 4 π 7 , {\displaystyle \operatorname {sen} ^{2}{\frac {4\pi }{7}},} que son los senos al cuadrado de los ángulos del triángulo.

La solución positiva de la ecuación cúbica

x 3 x 2 2 x 1 = 0 {\displaystyle x^{3} x^{2}-2x-1=0}

es igual 2 cos 2 π 7 , {\displaystyle 2\cos {\frac {2\pi }{7}},} que es el doble del coseno de uno de los ángulos del triángulo.[7]: p. 186–187 

Sen (2π/7), sen (4π/7) y sen (8π/7) son las raíces de[4]

x 3 7 2 x 2 7 8 = 0. {\displaystyle x^{3}-{\frac {\sqrt {7}}{2}}x^{2} {\frac {\sqrt {7}}{8}}=0.}

También se tiene que:[6]

sen A sen B sen C = 7 2 , {\displaystyle \operatorname {sen} A-\operatorname {sen} B-\operatorname {sen} C=-{\frac {\sqrt {7}}{2}},}
sen A sen B sen B sen C sen C sen A = 0 , {\displaystyle \operatorname {sen} A\operatorname {sen} B-\operatorname {sen} B\operatorname {sen} C \operatorname {sen} C\operatorname {sen} A=0,}
sen A sen B sen C = 7 8 . {\displaystyle \operatorname {sen} A\operatorname {sen} B\operatorname {sen} C={\frac {\sqrt {7}}{8}}.}
sen A , sen B , sen C  son las raíces de  x 3 7 2 x 2 7 8 = 0. {\displaystyle -\operatorname {sen} A,\operatorname {sen} B,\operatorname {sen} C{\text{ son las raíces de }}x^{3}-{\frac {\sqrt {7}}{2}}x^{2} {\frac {\sqrt {7}}{8}}=0.}

Para un entero n, sea

S ( n ) = ( sen A ) n sen n B sen n C . {\displaystyle S(n)=(-\operatorname {sen} {A})^{n} \operatorname {sen} ^{n}{B} \operatorname {sen} ^{n}{C}.}

Para n = 0, ..., 20,

S ( n ) = 3 , 7 2 , 7 2 2 , 7 2 , 7 3 2 4 , 7 7 2 4 , 7 5 2 5 , 7 2 7 2 7 , 7 2 5 2 8 , 7 25 7 2 9 , 7 2 9 2 9 , 7 2 13 7 2 11 , {\displaystyle S(n)=3,{\frac {\sqrt {7}}{2}},{\frac {7}{2^{2}}},{\frac {\sqrt {7}}{2}},{\frac {7\cdot 3}{2^{4}}},{\frac {7{\sqrt {7}}}{2^{4}}},{\frac {7\cdot 5}{2^{5}}},{\frac {7^{2}{\sqrt {7}}}{2^{7}}},{\frac {7^{2}\cdot 5}{2^{8}}},{\frac {7\cdot 25{\sqrt {7}}}{2^{9}}},{\frac {7^{2}\cdot 9}{2^{9}}},{\frac {7^{2}\cdot 13{\sqrt {7}}}{2^{11}}},}
7 2 33 2 11 , 7 2 3 7 2 9 , 7 4 5 2 14 , 7 2 179 7 2 15 , 7 3 131 2 16 , 7 3 3 7 2 12 , 7 3 493 2 18 , 7 3 181 7 2 18 , 7 5 19 2 19 . {\displaystyle {\frac {7^{2}\cdot 33}{2^{11}}},{\frac {7^{2}\cdot 3{\sqrt {7}}}{2^{9}}},{\frac {7^{4}\cdot 5}{2^{14}}},{\frac {7^{2}\cdot 179{\sqrt {7}}}{2^{15}}},{\frac {7^{3}\cdot 131}{2^{16}}},{\frac {7^{3}\cdot 3{\sqrt {7}}}{2^{12}}},{\frac {7^{3}\cdot 493}{2^{18}}},{\frac {7^{3}\cdot 181{\sqrt {7}}}{2^{18}}},{\frac {7^{5}\cdot 19}{2^{19}}}.}

Para n = 0, -1,, ..-20,

S ( n ) = 3 , 0 , 2 3 , 2 3 3 7 7 , 2 5 , 2 5 5 7 7 , 2 6 17 7 , 2 7 7 , 2 9 11 7 , 2 10 33 7 7 2 , 2 10 29 7 , 2 14 11 7 7 2 , 2 12 269 7 2 , {\displaystyle S(n)=3,0,2^{3},-{\frac {2^{3}\cdot 3{\sqrt {7}}}{7}},2^{5},-{\frac {2^{5}\cdot 5{\sqrt {7}}}{7}},{\frac {2^{6}\cdot 17}{7}},-2^{7}{\sqrt {7}},{\frac {2^{9}\cdot 11}{7}},-{\frac {2^{10}\cdot 33{\sqrt {7}}}{7^{2}}},{\frac {2^{10}\cdot 29}{7}},-{\frac {2^{14}\cdot 11{\sqrt {7}}}{7^{2}}},{\frac {2^{12}\cdot 269}{7^{2}}},}
2 13 117 7 7 2 , 2 14 51 7 , 2 21 17 7 7 3 , 2 17 237 7 2 , 2 17 1445 7 7 3 , 2 19 2203 7 3 , 2 19 1919 7 7 3 , 2 20 5851 7 3 . {\displaystyle -{\frac {2^{13}\cdot 117{\sqrt {7}}}{7^{2}}},{\frac {2^{14}\cdot 51}{7}},-{\frac {2^{21}\cdot 17{\sqrt {7}}}{7^{3}}},{\frac {2^{17}\cdot 237}{7^{2}}},-{\frac {2^{17}\cdot 1445{\sqrt {7}}}{7^{3}}},{\frac {2^{19}\cdot 2203}{7^{3}}},-{\frac {2^{19}\cdot 1919{\sqrt {7}}}{7^{3}}},{\frac {2^{20}\cdot 5851}{7^{3}}}.}
cos A , cos B , cos C  son las raíces de  x 3 1 2 x 2 1 2 x 1 8 = 0. {\displaystyle -\cos A,\cos B,\cos C{\text{ son las raíces de }}x^{3} {\frac {1}{2}}x^{2}-{\frac {1}{2}}x-{\frac {1}{8}}=0.}

Para cualquier entero n

C ( n ) = ( cos A ) n cos n B cos n C . {\displaystyle C(n)=(-\cos {A})^{n} \cos ^{n}{B} \cos ^{n}{C}.}

Para n = 0, 1, ... 10,

C ( n ) = 3 , 1 2 , 5 4 , 1 2 , 13 16 , 1 2 , 19 32 , 57 128 , 117 256 , 193 512 , 185 512 , . . . {\displaystyle C(n)=3,-{\frac {1}{2}},{\frac {5}{4}},-{\frac {1}{2}},{\frac {13}{16}},-{\frac {1}{2}},{\frac {19}{32}},-{\frac {57}{128}},{\frac {117}{256}},-{\frac {193}{512}},{\frac {185}{512}},...}
C ( n ) = 3 , 4 , 24 , 88 , 416 , 1824 , 8256 , 36992 , 166400 , 747520 , 3359744 , . . . {\displaystyle C(-n)=3,-4,24,-88,416,-1824,8256,-36992,166400,-747520,3359744,...}
tan A , tan B , tan C  son las raíces de  x 3 7 x 2 7 x 7 = 0. {\displaystyle \tan A,\tan B,\tan C{\text{ son las raíces de }}x^{3} {\sqrt {7}}x^{2}-7x {\sqrt {7}}=0.}
tan 2 A , tan 2 B , tan 2 C  son las raíces de  x 3 21 x 2 35 x 7 = 0. {\displaystyle \tan ^{2}A,\tan ^{2}B,\tan ^{2}C{\text{ son las raíces de }}x^{3}-21x^{2} 35x-7=0.}

Para un entero n, sea

T ( n ) = tan n A tan n B tan n C . {\displaystyle T(n)=\tan ^{n}{A} \tan ^{n}{B} \tan ^{n}{C}.}

Para n = 0, 1, ... 10,

T ( n ) = 3 , 7 , 7 3 , 31 7 , 7 53 , 7 87 7 , 7 1011 , 7 2 239 7 , 7 2 2771 , 7 32119 7 , 7 2 53189 , {\displaystyle T(n)=3,-{\sqrt {7}},7\cdot 3,-31{\sqrt {7}},7\cdot 53,-7\cdot 87{\sqrt {7}},7\cdot 1011,-7^{2}\cdot 239{\sqrt {7}},7^{2}\cdot 2771,-7\cdot 32119{\sqrt {7}},7^{2}\cdot 53189,}
T ( n ) = 3 , 7 , 5 , 25 7 7 , 19 , 103 7 7 , 563 7 , 7 9 7 , 2421 7 , 13297 7 7 2 , 10435 7 , . . . {\displaystyle T(-n)=3,{\sqrt {7}},5,{\frac {25{\sqrt {7}}}{7}},19,{\frac {103{\sqrt {7}}}{7}},{\frac {563}{7}},7\cdot 9{\sqrt {7}},{\frac {2421}{7}},{\frac {13297{\sqrt {7}}}{7^{2}}},{\frac {10435}{7}},...}

También se tiene que[6][8]

tan A 4 sen B = 7 , {\displaystyle \tan A-4\operatorname {sen} B=-{\sqrt {7}},}
tan B 4 sen C = 7 , {\displaystyle \tan B-4\operatorname {sen} C=-{\sqrt {7}},}
tan C 4 sen A = 7 . {\displaystyle \tan C 4\operatorname {sen} A=-{\sqrt {7}}.}

Así mismo[4]

cot 2 A = 1 2 tan C 7 , {\displaystyle \cot ^{2}A=1-{\frac {2\tan C}{\sqrt {7}}},}
cot 2 B = 1 2 tan A 7 , {\displaystyle \cot ^{2}B=1-{\frac {2\tan A}{\sqrt {7}}},}
cot 2 C = 1 2 tan B 7 . {\displaystyle \cot ^{2}C=1-{\frac {2\tan B}{\sqrt {7}}}.}

También se tiene que[4]

cos A = 1 2 4 7 sen 3 C , {\displaystyle \cos A=-{\frac {1}{2}} {\frac {4}{\sqrt {7}}}\operatorname {sen} ^{3}C,}
cos 2 A = 3 4 2 7 sen 3 A , {\displaystyle \cos ^{2}A={\frac {3}{4}} {\frac {2}{\sqrt {7}}}\operatorname {sen} ^{3}A,}
cot A = 3 7 4 7 cos B , {\displaystyle \cot A={\frac {3}{\sqrt {7}}} {\frac {4}{\sqrt {7}}}\cos B,}
cot 2 A = 3 8 7 sen A , {\displaystyle \cot ^{2}A=3 {\frac {8}{\sqrt {7}}}\operatorname {sen} A,}
cot A = 7 8 7 sen 2 B , {\displaystyle \cot A={\sqrt {7}} {\frac {8}{\sqrt {7}}}\operatorname {sen} ^{2}B,}
csc 3 A = 6 7 2 7 tan 2 C , {\displaystyle \csc ^{3}A=-{\frac {6}{\sqrt {7}}} {\frac {2}{\sqrt {7}}}\tan ^{2}C,}
sec A = 2 4 cos C , {\displaystyle \sec A=2 4\cos C,}
sec A = 6 8 sen 2 B , {\displaystyle \sec A=6-8\operatorname {sen} ^{2}B,}
sec A = 4 16 7 sen 3 B , {\displaystyle \sec A=4-{\frac {16}{\sqrt {7}}}\operatorname {sen} ^{3}B,}
sen 2 A = 1 2 1 2 cos B , {\displaystyle \operatorname {sen} ^{2}A={\frac {1}{2}} {\frac {1}{2}}\cos B,}
sen 3 A = 7 8 7 4 cos B , {\displaystyle \operatorname {sen} ^{3}A=-{\frac {\sqrt {7}}{8}} {\frac {\sqrt {7}}{4}}\cos B,}

También se tiene que[9]

sen 3 B sen C sen 3 C sen A sen 3 A sen B = 0 , {\displaystyle \operatorname {sen} ^{3}B\operatorname {sen} C-\operatorname {sen} ^{3}C\operatorname {sen} A-\operatorname {sen} ^{3}A\operatorname {sen} B=0,}
sen B sen 3 C sen C sen 3 A sen A sen 3 B = 7 2 4 , {\displaystyle \operatorname {sen} B\operatorname {sen} ^{3}C-\operatorname {sen} C\operatorname {sen} ^{3}A-\operatorname {sen} A\operatorname {sen} ^{3}B={\frac {7}{2^{4}}},}
sen 4 B sen C sen 4 C sen A sen 4 A sen B = 0 , {\displaystyle \operatorname {sen} ^{4}B\operatorname {sen} C-\operatorname {sen} ^{4}C\operatorname {sen} A \operatorname {sen} ^{4}A\operatorname {sen} B=0,}
sen B sen 4 C sen C sen 4 A sen A sen 4 B = 7 7 2 5 , {\displaystyle \operatorname {sen} B\operatorname {sen} ^{4}C \operatorname {sen} C\operatorname {sen} ^{4}A-\operatorname {sen} A\operatorname {sen} ^{4}B={\frac {7{\sqrt {7}}}{2^{5}}},}
sen 11 B sen 3 C sen 11 C sen 3 A sen 11 A sen 3 B = 0 , {\displaystyle \operatorname {sen} ^{11}B\operatorname {sen} ^{3}C-\operatorname {sen} ^{11}C\operatorname {sen} ^{3}A-\operatorname {sen} ^{11}A\operatorname {sen} ^{3}B=0,}
sen 3 B sen 11 C sen 3 C sen 11 A sen 3 A sen 11 B = 7 3 17 2 14 . {\displaystyle \operatorname {sen} ^{3}B\operatorname {sen} ^{11}C-\operatorname {sen} ^{3}C\operatorname {sen} ^{11}A-\operatorname {sen} ^{3}A\operatorname {sen} ^{11}B={\frac {7^{3}\cdot 17}{2^{14}}}.}

También se cumplen identidades de tipo Ramanujan,[10]

2 sen ( 2 π 7 ) 3 2 sen ( 4 π 7 ) 3 2 sen ( 8 π 7 ) 3 = {\displaystyle {\sqrt[{3}]{2\operatorname {sen}({\frac {2\pi }{7}})}} {\sqrt[{3}]{2\operatorname {sen}({\frac {4\pi }{7}})}} {\sqrt[{3}]{2\operatorname {sen}({\frac {8\pi }{7}})}}=}
....... ( 7 18 ) 7 3 6 3 ( 5 3 7 3 3 4 3 7 3 3 ) 3 {\displaystyle {\text{.......}}\left(-{\sqrt[{18}]{7}}\right){\sqrt[{3}]{-{\sqrt[{3}]{7}} 6 3\left({\sqrt[{3}]{5-3{\sqrt[{3}]{7}}}} {\sqrt[{3}]{4-3{\sqrt[{3}]{7}}}}\right)}}}
1 2 sen ( 2 π 7 ) 3 1 2 sen ( 4 π 7 ) 3 1 2 sen ( 8 π 7 ) 3 = {\displaystyle {\frac {1}{\sqrt[{3}]{2\operatorname {sen}({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{2\operatorname {sen}({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{2\operatorname {sen}({\frac {8\pi }{7}})}}}=}
....... ( 1 7 18 ) 6 3 ( 5 3 7 3 3 4 3 7 3 3 ) 3 {\displaystyle {\text{.......}}\left(-{\frac {1}{\sqrt[{18}]{7}}}\right){\sqrt[{3}]{6 3\left({\sqrt[{3}]{5-3{\sqrt[{3}]{7}}}} {\sqrt[{3}]{4-3{\sqrt[{3}]{7}}}}\right)}}}
4 sen 2 ( 2 π 7 ) 3 4 sen 2 ( 4 π 7 ) 3 4 sen 2 ( 8 π 7 ) 3 = {\displaystyle {\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {2\pi }{7}})}} {\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {4\pi }{7}})}} {\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {8\pi }{7}})}}=}
....... ( 49 18 ) 49 3 6 3 ( 12 3 ( 49 3 2 7 3 ) 3 11 3 ( 49 3 2 7 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left({\sqrt[{18}]{49}}\right){\sqrt[{3}]{{\sqrt[{3}]{49}} 6 3\left({\sqrt[{3}]{12 3({\sqrt[{3}]{49}} 2{\sqrt[{3}]{7}})}} {\sqrt[{3}]{11 3({\sqrt[{3}]{49}} 2{\sqrt[{3}]{7}})}}\right)}}}
1 4 sen 2 ( 2 π 7 ) 3 1 4 sen 2 ( 4 π 7 ) 3 1 4 sen 2 ( 8 π 7 ) 3 = {\displaystyle {\frac {1}{\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{4\operatorname {sen} ^{2}({\frac {8\pi }{7}})}}}=}
....... ( 1 49 18 ) 2 7 3 6 3 ( 12 3 ( 49 3 2 7 3 ) 3 11 3 ( 49 3 2 7 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left({\frac {1}{\sqrt[{18}]{49}}}\right){\sqrt[{3}]{2{\sqrt[{3}]{7}} 6 3\left({\sqrt[{3}]{12 3({\sqrt[{3}]{49}} 2{\sqrt[{3}]{7}})}} {\sqrt[{3}]{11 3({\sqrt[{3}]{49}} 2{\sqrt[{3}]{7}})}}\right)}}}
2 cos ( 2 π 7 ) 3 2 cos ( 4 π 7 ) 3 2 cos ( 8 π 7 ) 3 = 5 3 7 3 3 {\displaystyle {\sqrt[{3}]{2\cos({\frac {2\pi }{7}})}} {\sqrt[{3}]{2\cos({\frac {4\pi }{7}})}} {\sqrt[{3}]{2\cos({\frac {8\pi }{7}})}}={\sqrt[{3}]{5-3{\sqrt[{3}]{7}}}}}
1 2 cos ( 2 π 7 ) 3 1 2 cos ( 4 π 7 ) 3 1 2 cos ( 8 π 7 ) 3 = 4 3 7 3 3 {\displaystyle {\frac {1}{\sqrt[{3}]{2\cos({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{2\cos({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{2\cos({\frac {8\pi }{7}})}}}={\sqrt[{3}]{4-3{\sqrt[{3}]{7}}}}}
4 cos 2 ( 2 π 7 ) 3 4 cos 2 ( 4 π 7 ) 3 4 cos 2 ( 8 π 7 ) 3 = 11 3 ( 2 7 3 49 3 ) 3 {\displaystyle {\sqrt[{3}]{4\cos ^{2}({\frac {2\pi }{7}})}} {\sqrt[{3}]{4\cos ^{2}({\frac {4\pi }{7}})}} {\sqrt[{3}]{4\cos ^{2}({\frac {8\pi }{7}})}}={\sqrt[{3}]{11 3(2{\sqrt[{3}]{7}} {\sqrt[{3}]{49}})}}}
1 4 cos 2 ( 2 π 7 ) 3 1 4 cos 2 ( 4 π 7 ) 3 1 4 cos 2 ( 8 π 7 ) 3 = 12 3 ( 2 7 3 49 3 ) 3 {\displaystyle {\frac {1}{\sqrt[{3}]{4\cos ^{2}({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{4\cos ^{2}({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{4\cos ^{2}({\frac {8\pi }{7}})}}}={\sqrt[{3}]{12 3(2{\sqrt[{3}]{7}} {\sqrt[{3}]{49}})}}}
tan ( 2 π 7 ) 3 tan ( 4 π 7 ) 3 tan ( 8 π 7 ) 3 = {\displaystyle {\sqrt[{3}]{\tan({\frac {2\pi }{7}})}} {\sqrt[{3}]{\tan({\frac {4\pi }{7}})}} {\sqrt[{3}]{\tan({\frac {8\pi }{7}})}}=}
....... ( 7 18 ) 7 3 6 3 ( 5 3 ( 7 3 49 3 ) 3 3 3 ( 7 3 49 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left(-{\sqrt[{18}]{7}}\right){\sqrt[{3}]{{\sqrt[{3}]{7}} 6 3\left({\sqrt[{3}]{5 3({\sqrt[{3}]{7}}-{\sqrt[{3}]{49}})}} {\sqrt[{3}]{-3 3({\sqrt[{3}]{7}}-{\sqrt[{3}]{49}})}}\right)}}}
1 tan ( 2 π 7 ) 3 1 tan ( 4 π 7 ) 3 1 tan ( 8 π 7 ) 3 = {\displaystyle {\frac {1}{\sqrt[{3}]{\tan({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{\tan({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{\tan({\frac {8\pi }{7}})}}}=}
....... ( 1 7 18 ) 49 3 6 3 ( 5 3 ( 7 3 49 3 ) 3 3 3 ( 7 3 49 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left(-{\frac {1}{\sqrt[{18}]{7}}}\right){\sqrt[{3}]{-{\sqrt[{3}]{49}} 6 3\left({\sqrt[{3}]{5 3({\sqrt[{3}]{7}}-{\sqrt[{3}]{49}})}} {\sqrt[{3}]{-3 3({\sqrt[{3}]{7}}-{\sqrt[{3}]{49}})}}\right)}}}
tan 2 ( 2 π 7 ) 3 tan 2 ( 4 π 7 ) 3 tan 2 ( 8 π 7 ) 3 = {\displaystyle {\sqrt[{3}]{\tan ^{2}({\frac {2\pi }{7}})}} {\sqrt[{3}]{\tan ^{2}({\frac {4\pi }{7}})}} {\sqrt[{3}]{\tan ^{2}({\frac {8\pi }{7}})}}=}
....... ( 49 18 ) 3 49 3 6 3 ( 89 3 ( 3 49 3 5 7 3 ) 3 25 3 ( 3 49 3 5 7 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left({\sqrt[{18}]{49}}\right){\sqrt[{3}]{3{\sqrt[{3}]{49}} 6 3\left({\sqrt[{3}]{89 3(3{\sqrt[{3}]{49}} 5{\sqrt[{3}]{7}})}} {\sqrt[{3}]{25 3(3{\sqrt[{3}]{49}} 5{\sqrt[{3}]{7}})}}\right)}}}
1 tan 2 ( 2 π 7 ) 3 1 tan 2 ( 4 π 7 ) 3 1 tan 2 ( 8 π 7 ) 3 = {\displaystyle {\frac {1}{\sqrt[{3}]{\tan ^{2}({\frac {2\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{\tan ^{2}({\frac {4\pi }{7}})}}} {\frac {1}{\sqrt[{3}]{\tan ^{2}({\frac {8\pi }{7}})}}}=}
....... ( 1 49 18 ) 5 7 3 6 3 ( 89 3 ( 3 49 3 5 7 3 ) 3 25 3 ( 3 49 3 5 7 3 ) 3 ) 3 {\displaystyle {\text{.......}}\left({\frac {1}{\sqrt[{18}]{49}}}\right){\sqrt[{3}]{5{\sqrt[{3}]{7}} 6 3\left({\sqrt[{3}]{89 3(3{\sqrt[{3}]{49}} 5{\sqrt[{3}]{7}})}} {\sqrt[{3}]{25 3(3{\sqrt[{3}]{49}} 5{\sqrt[{3}]{7}})}}\right)}}}

También se tiene que[9]

cos ( 2 π 7 ) / cos ( 4 π 7 ) 3 cos ( 4 π 7 ) / cos ( 8 π 7 ) 3 cos ( 8 π 7 ) / cos ( 2 π 7 ) 3 = 7 3 . {\displaystyle {\sqrt[{3}]{\cos({\frac {2\pi }{7}})/\cos({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos({\frac {4\pi }{7}})/\cos({\frac {8\pi }{7}})}} {\sqrt[{3}]{\cos({\frac {8\pi }{7}})/\cos({\frac {2\pi }{7}})}}=-{\sqrt[{3}]{7}}.}
cos ( 4 π 7 ) / cos ( 2 π 7 ) 3 cos ( 8 π 7 ) / cos ( 4 π 7 ) 3 cos ( 2 π 7 ) / cos ( 8 π 7 ) 3 = 0. {\displaystyle {\sqrt[{3}]{\cos({\frac {4\pi }{7}})/\cos({\frac {2\pi }{7}})}} {\sqrt[{3}]{\cos({\frac {8\pi }{7}})/\cos({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos({\frac {2\pi }{7}})/\cos({\frac {8\pi }{7}})}}=0.}
2 sen ( 2 π 7 3 2 sen ( 4 π 7 3 2 sen ( 8 π 7 3 = ( 7 18 ) 7 3 6 3 ( 5 3 7 3 3 4 3 7 3 3 ) 3 {\displaystyle {\sqrt[{3}]{2\operatorname {sen}({2\pi }{7}}} {\sqrt[{3}]{2\operatorname {sen}({4\pi }{7}}} {\sqrt[{3}]{2\operatorname {sen}({8\pi }{7}}}=\left(-{\sqrt[{18}]{7}}\right){\sqrt[{3}]{-{\sqrt[{3}]{7}} 6 3\left({\sqrt[{3}]{5-3{\sqrt[{3}]{7}}}} {\sqrt[{3}]{4-3{\sqrt[{3}]{7}}}}\right)}}}
cos 4 ( 4 π 7 ) / cos ( 2 π 7 ) 3 cos 4 ( 8 π 7 ) / cos ( 4 π 7 ) 3 cos 4 ( 2 π 7 ) / cos ( 8 π 7 ) 3 = 49 3 / 2. {\displaystyle {\sqrt[{3}]{\cos ^{4}({\frac {4\pi }{7}})/\cos({\frac {2\pi }{7}})}} {\sqrt[{3}]{\cos ^{4}({\frac {8\pi }{7}})/\cos({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos ^{4}({\frac {2\pi }{7}})/\cos({\frac {8\pi }{7}})}}=-{\sqrt[{3}]{49}}/2.}
cos 5 ( 2 π 7 ) / cos 2 ( 4 π 7 ) 3 cos 5 ( 4 π 7 ) / cos 2 ( 8 π 7 ) 3 cos 5 ( 8 π 7 ) / cos 2 ( 2 π 7 ) 3 = 0. {\displaystyle {\sqrt[{3}]{\cos ^{5}({\frac {2\pi }{7}})/\cos ^{2}({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos ^{5}({\frac {4\pi }{7}})/\cos ^{2}({\frac {8\pi }{7}})}} {\sqrt[{3}]{\cos ^{5}({\frac {8\pi }{7}})/\cos ^{2}({\frac {2\pi }{7}})}}=0.}
cos 5 ( 4 π 7 ) / cos 2 ( 2 π 7 ) 3 cos 5 ( 8 π 7 ) / cos 2 ( 4 π 7 ) 3 cos 5 ( 2 π 7 ) / cos 2 ( 9 π 7 ) 3 = 3 7 3 / 2. {\displaystyle {\sqrt[{3}]{\cos ^{5}({\frac {4\pi }{7}})/\cos ^{2}({\frac {2\pi }{7}})}} {\sqrt[{3}]{\cos ^{5}({\frac {8\pi }{7}})/\cos ^{2}({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos ^{5}({\frac {2\pi }{7}})/\cos ^{2}({\frac {9\pi }{7}})}}=-3*{\sqrt[{3}]{7}}/2.}
cos 14 ( 2 π 7 ) / cos 5 ( 4 π 7 ) 3 cos 14 ( 4 π 7 ) / cos 5 ( 8 π 7 ) 3 cos 14 ( 8 π 7 ) / cos 5 ( 2 π 7 3 = 0. {\displaystyle {\sqrt[{3}]{\cos ^{14}({\frac {2\pi }{7}})/\cos ^{5}({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos ^{14}({\frac {4\pi }{7}})/\cos ^{5}({\frac {8\pi }{7}})}} {\sqrt[{3}]{\cos ^{14}({\frac {8\pi }{7}})/\cos ^{5}({\frac {2\pi }{7}}}}=0.}
cos 14 ( 4 π 7 ) / cos 5 ( 2 π 7 ) 3 cos 14 ( 8 π 7 ) / cos 5 ( 4 π 7 ) 3 cos 14 ( 2 π 7 ) / cos 5 ( 8 π 7 ) 3 = 61 7 3 / 8. {\displaystyle {\sqrt[{3}]{\cos ^{14}({\frac {4\pi }{7}})/\cos ^{5}({\frac {2\pi }{7}})}} {\sqrt[{3}]{\cos ^{14}({\frac {8\pi }{7}})/\cos ^{5}({\frac {4\pi }{7}})}} {\sqrt[{3}]{\cos ^{14}({\frac {2\pi }{7}})/\cos ^{5}({\frac {8\pi }{7}})}}=-61*{\sqrt[{3}]{7}}/8.}

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